Here goes: today we checked our linear inequalities, and I would say that most of you have some serious redoing to do. Make sure that happens, since they will be on tomorrow's quiz. Then we started Project 7. You are creating a graph of a linear equations, based on a constant ratio.
PROJECT 7- Constant ratio
In this project you will create a poster with a graph of a linear equation.
1) Choose a realationship with a constant ratio. Example: 5 fingers on a hand.
2) Graph the linear relationship using only Quadrant 1. Label the axes, and mark at least 3 points.
3) Label one of the points, explaining what it means (i.e. 3 hands, 15 fingers)
4) Label the y-intercept, explaining what it means (i.e. when there are no hands, there are no fingers.)
5) Label the slope, using the rise/run. Explain what the slope means (when we add one hand, we add five fingers).
6) Write the equation of the line you have graphed. (In my case, y= 5x.)
7) Decorate the edges of your poster to reflect what the poster is about.
Grading:
an A poster will have followed all the directions above accurately, be neat and colorful, and reflect your understanding of linear equations.
Due: next Tuesday (December 16th.)
There you go! Have fun!
Ms V
Thursday, December 11, 2008
Wednesday, December 10, 2008
Graphing linear inequalities
Okay okay okay, I've been very bad about this. All I can say is I'll try to be better. So here goes...
Today we learned about graphing linear inequalities. Although it is a challenging skill, most of you seem to have gotten it pretty well. The first step is to graph the line, either with a t-table or by using slope-intercept. Don't forget that if there is an equal sign the line is solid, but if there is no equal sign, the line is dotted. Next, choose a point from each side of the line. Plug in the x and the y for each point and see which one gives you a true answer. The one that has a true statement at the end is on the side that should be shaded. The one that got a "no" is on the side that is unshaded. That's all. Not as hard as some of you feared.
Tonight's homework is to graph the following linear inequalities:
1) y > 2x+1
2) y<-3x
3) y<(1/2)x-5
4) y>(3/4)x-5
(Number 1 and 3 have equal signs, but I don't know how to format that on the computer.
Ciao!
Ms V
Today we learned about graphing linear inequalities. Although it is a challenging skill, most of you seem to have gotten it pretty well. The first step is to graph the line, either with a t-table or by using slope-intercept. Don't forget that if there is an equal sign the line is solid, but if there is no equal sign, the line is dotted. Next, choose a point from each side of the line. Plug in the x and the y for each point and see which one gives you a true answer. The one that has a true statement at the end is on the side that should be shaded. The one that got a "no" is on the side that is unshaded. That's all. Not as hard as some of you feared.
Tonight's homework is to graph the following linear inequalities:
1) y > 2x+1
2) y<-3x
3) y<(1/2)x-5
4) y>(3/4)x-5
(Number 1 and 3 have equal signs, but I don't know how to format that on the computer.
Ciao!
Ms V
Tuesday, December 2, 2008
Linear functions and slope
So today we learned how to graph a linear function (which is an equation with 2 variables and no exponents. We graph this by using a t-table. Plug in the value for x and get the value for y.
For example:
y=2x
x y
-1 -2
0 0
1 2.
From this t-table you create ordered pairs and graph them. If you've done it correctly, they will lie in a line.
We also learned about slope. To find the slope, choose any two points on the line. If you count up (the rise) and across (the run) and divide (rise over run) you will have the slope.
For homework tonight you have 4 equations to graph and every period but Period 1 needs to find the slope.
The equations are
1) y=3x-2
2) y=x
3) y=x+1
4) y=1/2 x.
good luck and see you tomorrow:o)
Ms V
For example:
y=2x
x y
-1 -2
0 0
1 2.
From this t-table you create ordered pairs and graph them. If you've done it correctly, they will lie in a line.
We also learned about slope. To find the slope, choose any two points on the line. If you count up (the rise) and across (the run) and divide (rise over run) you will have the slope.
For homework tonight you have 4 equations to graph and every period but Period 1 needs to find the slope.
The equations are
1) y=3x-2
2) y=x
3) y=x+1
4) y=1/2 x.
good luck and see you tomorrow:o)
Ms V
Monday, December 1, 2008
Relations and Functions
Hey all! So sorry about the lack of blogging. I guess the holiday spirit just took over. But I'm back on it now.
Today we learned about relations (a set of ordered pairs) and functions (a relation in which each member of the domain maps to exactly on member of the range.) We learned that you can tell whether or not a relation is a function in one of two ways. First, you can map the domain and range. If each member of the domain has exactly one arrow coming from it, it's a function. If any member of the domain has more than one arrow coming from it, the relation is not a function. The second way is to use the vertical line test. If a vertical line slid from left to right on a graph hits more than one point at any time, the relation is not a function. If it doesn't, it is a function.
So that's that. And today is World AIDS day, so take a moment to think about all the people in the world who have suffered with this terrible disease and then think once again about how lucky you are!
See you tomorrow!
Ms V
Today we learned about relations (a set of ordered pairs) and functions (a relation in which each member of the domain maps to exactly on member of the range.) We learned that you can tell whether or not a relation is a function in one of two ways. First, you can map the domain and range. If each member of the domain has exactly one arrow coming from it, it's a function. If any member of the domain has more than one arrow coming from it, the relation is not a function. The second way is to use the vertical line test. If a vertical line slid from left to right on a graph hits more than one point at any time, the relation is not a function. If it doesn't, it is a function.
So that's that. And today is World AIDS day, so take a moment to think about all the people in the world who have suffered with this terrible disease and then think once again about how lucky you are!
See you tomorrow!
Ms V
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